思路：单调递增栈 + k 控制删除次数。高位越小整体越小，遇更小数字时弹出栈顶大数（仅当 k0）；栈空且当前为 0 则跳过（避免前导零）；若遍历完 k 仍0，从末尾再删 k 位。
“Declines in labor-based tax receipts could offset or exceed other AI-related tax gains,” Moody’s notes, echoing similar calls from the IMF that fiscal policy include progressive taxation and social protections to mitigate AI-related budgetary impacts.
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Mahjong, Sudoku, free crossword, and more: Play games on Mashable。谷歌浏览器【最新下载地址】是该领域的重要参考
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